C++ lambda expressions - How does the compiler interpret them?
C++ lambda expressions - How does the compiler interpret them?
27117-Aug-2023
Updated on 18-Aug-2023
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1 Answers
Aryan Kumar
18-Aug-2023C++ lambda expressions are interpreted by the compiler as anonymous functions. The compiler converts the lambda expression to a normal function, which is then called when the lambda expression is evaluated.
The compiler first analyzes the lambda expression to determine its type. The type of the lambda expression is the type of the value that it returns. The compiler then generates code to create a new function object of the appropriate type. The function object is then stored in a temporary variable.
When the lambda expression is evaluated, the compiler calls the function object. The function object then executes the code that was defined in the lambda expression.
Here is an example of a C++ lambda expression:
C++
This lambda expression defines a function that takes an integer as its input and returns the square of the integer. The compiler will convert this lambda expression to a normal function, which is then called when the lambda expression is evaluated.
The compiler interprets lambda expressions as anonymous functions because it makes the code more concise and readable. Lambda expressions can also be used to create closures, which are functions that can access variables from the scope in which they were defined.